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旧 Dec 5th, 2007, 08:04     #1
erguotou
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作者: f225 查看帖子
多谢楼上几位了,那我就不费那劲了。

还有个问题,如果119/118.7的LNB放中间,再加两个LNB收110和129,象这个照片里的那样,他们和中间那个LNB的距离是多少啊?有什么公式能算出来吗?
[IMG]http://i1.tinypic.com/7x9pekp.jpg[/IM]
LNB位置间距 = LNB头部到锅弧顶距离 x tan(卫星角度差/2), or

= LNB头部到锅弧顶距离 x 卫星角度差 x 3.14/ 360

例如,若从lnb头到锅弧顶距离为50cm,110与119差9度,
间距 = 50*tan(9/2) = 3.9cm
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